If the 3rd and 9th term of an ap are 4 and -8 respectively then which term of AP is zero

fifth term

Step-by-step explanation:

The n th term of an AP is

= a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₃ = 4 and a₉ = - 8 , then

a₁ + 2d = 4 → (1)

a₁ + 8d = - 8 → (2)

Subtract (1) from (2)

6d = - 12 ( divide both sides by 6 )

d = - 2

Substitute d = - 2 into (1)

a₁ + 2(- 2) = 4

a₁ - 4 = 4 ( add 4 to both sides )

a₁ = 8

Thus equating the n th term formula to zero and solving for n

8 - 2(n - 1) = 0 ( subtract 8 from both sides )

- 2(n - 1) = - 8 ( divide both sides by - 2

n - 1 = 4 ( add 1 to both sides )

n = 5

The fifth term is equal to zero

ok so the answer to your question is simple as long as you look at the different dimensions that contain the exemplary letters that combined in the right order give you words that eventually within the 5th dimension will conform and give you the correct answer to your question. hope i , stop looking at this easily, look at it with a spectral view.

step-by-step explanation:

told you

idk wbu

step-by-step explanation: