A rectangular garden has a perimeter of 578 yds. The length is one more than three times the width.
Find the dimensions of the garden.

Step-by-step explanation:

Perimeter of a rectangle = 2l + 2w

where

l is the length

w is the width

From the question

Perimeter = 578 yds

The statement

The length is one more than three times the width is written as

l = 1 + 3w

Substitute the expression into the above formula and solve for the width

That's

578 = 2(1 + 3w) + 2w

578 = 2 + 6w + 2w

8w = 576

Divide both sides by 8

w = 72

Substitute w = 72 into l = 1 + 3w

That's

l = 1 + 3(72)

l = 216 + 1

l = 217

Therefore the dimensions are

length = 217 yd

width = 72 yd

Hope this helps you

you should pay $0.88

what is the image?

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)