A rectangular garden has a perimeter of 578 yds. The length is one more than three times the width.
Find the dimensions of the garden.

Width (w) = 72 yds

Length (L) = 217 yds

Step-by-step explanation:

Let L represent the length.

Let w represent the width.

From the question given above:

Perimeter (P) = 578 yds.

Length (L) is one more than three times the width (w). This can be written as. Follow:

three times the width (w) = 3w

Therefore, the length (L) is given by:

L = 1 + 3w

Next, we shall determine the value of length (L) and width (w). This can be obtained as follow:

Recall:

Perimeter of rectangle is given by:

P = 2(L + w)

P = 2L + 2w

Perimeter (P) = 578 yds.

Length (L) = 1 + 3w

Width (w) = w

P = 2L + 2w

578 = 2(1 + 3w) + 2w

Clear bracket

578 = 2 + 6w + 2w

578 = 2 + 8w

Collect like terms

578 - 2 = 8w

576 = 8w

Divide both side by 8

w = 576/8

w = 72

Therefore, the width is 72 yds

L = 1 + 3w

w = 72

L = 1 + 3(72)

L = 1 + 216

L = 217

Therefore, the length is 217 yds.

The dimensions of the garden is given below:

Width (w) = 72 yds.

Length (L) = 217 yds.

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step-by-step explanation:

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)