Write an equation of the line below.
(0,-2) (8,-4)

Step-by-step explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

First of all to find the equation of the line we must first find the slope.

The slope of the line using points

(0,-2) (8,-4) is

Now using one of the points and the slope we can find the equation of the line.

Equation of the line using point (0 , - 2) and slope - 1/4 is

We have the final answer as

Hope this helps you

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

idk

step-by-step explanation: