I need step by step explanation for thisss >33

Step-by-step explanation:

The question says find the number eight times of a certain two digit number exceeding the number 19.The tens digit than the units digit . So,you have to multiply eight to a two digit number exceeding 19 so you find a number exceeding 19 which would have to be able to to multiply by eight to exceed the number 19

find the number eight times of a two digit number higher than the number nineteen. The tens digit than the units digit .you have to multiply 8 to a 2 digit number exceeding nineteen so you find a number exceeding ninteen which would have to be able to to times by 8 to go higher than the number nineteen

it is b)

hope this : )

step-by-step explanation:

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.