Rationalize the denominator of sqrt32/(sqrt16-sqrt2). The answer can be written as )AsqrtB+C)/D, where A, B, C, and D are integers, D is positive, and B is not divisible by the square of any prime. Find the minimum possible value of A+B+C+D.

Step-by-step explanation:

It says it can be written in the form of

where A, B, C and D are integers, D is positive and B is not divisible by square of any prime

Rationalize equation 1:

in denominator, use (a + b)(a - b) =

After multiplying numerator and denominator you should get

this is in the form

where A = 16, B = 2, C = 8, and D = 14

hope this helps you ^^

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5