The number of real solutions to the quadratic equ
5a² + 30a + 45 = 0

The answer is 1.

There is one unique real solution, which is x = -3.

Hello, please consider the following.

Thank you

two equal, real solutions

Step-by-step explanation:

The quickest way to determine this is to find the discriminant b^2 - 4ac.  If this determinant (D) is > 0, the quadratic has two different real roots; if + 0, the quadratic has two equal real roots, and if < 0, the quadratic has two imaginary or complex roots.

Here a = 5, b = 30 and c = 45.  The discriminant is

30^2 - 4(5)(45)  =  900 - 900 = 0

and so this quadratic has two equal, real solutions.

in the attachment.   i didn't see your choices.   the word which means there is choices.

step-by-step explanation:

(x,y)

x tells you how much left or right you go from the origin

y tells you how much down or up you go from the origin

so for example (-3,2), you go left 3 and up twice. i denoted which of the ordered pairs is which in my graph.