The length of a new rectangular playing field is 4 yards longer than quadruple the width. If the perimeter of the rectangular playing field is 488 yards, what are its dimensions?

w = 48

w = 196

Step-by-step explanation:

Width = w

Length = l = 4 + 4w

Use the values for length and width above along with the given value for perimeter in the formula for perimeter.

P = 2l + 2w

488 = 2(4 + 4w) + 2w

488 = 8 + 8w + 2w

488 = 8 + 10w

488 - 8 = (8 + 10w) - 8

480 = 10w

(480)/10 = (10w)/10

48 = w

w = 48

The width is 48 yards.  Use this value to solve for length.

l = 4 + 4w

l = 4 + 4(48)

l = 4 + 192

l = 196

The length is 196 yards.

answer: idk

step-by-step explanation:

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: