A triangle has coordinates of A(1, 2), B(4, 6), and C(4, -3). 1. If the triangle is translated 2 units right, what are the new coordinates?

2. If ΔABC is reflected over the x-axis, what are the new coordinates?

Please show all work and not just the answer.

1 = (3,2) B= (6, 6) C = (6, -3)

Move two to the right since left and right deals with the x axis, add two to the x’s

2 = (1, -2) B = (4, -6) C = (4, 3)

Reflecting across the x axis means the formula is (x, -y) so switch the sign of the y’s

1) A (3,2), B (6,6), C (6,-3)

2) A (1,-2), B (4,-6), C (4,3)

Step-by-step explanation:

1) Each of the x-values goes up two.

A (1,2) becomes (3,2)

B (4,6) becomes (6,6)

C (4,-3) becomes (6,-3)

2). I assume they mean the ORIGINAL ABC, not the one you just translated 2 units to the right.

To do this, you just multiply each y-value times negative one.

A (1,2) becomes (1,-2)

B (4,6) becomes (4,-6)

C (4,-3) becomes (4,3)

7.3

step-by-step explanation:

question 1: step-by-step explanation:

1/4 of 84 = 84÷4= 21