Use Stokes' Theorem to calculate . F = 5yi + 7xj + z3k; C: the counterclockwise path around the perimeter of the triangle in the x-y plane formed from the x-axis, y-axis , and the line y = 5 - 2x (Hint: n = k)

hello your question is incomplete attached is the complete question

answer : 25/2 ( A )

Step-by-step explanation:

using Stokes' Theorem to calculate

F = 5yi + 7xj  +

line y = 5 - 2x

attached below is the remaining part of the solution to the question

25.3

step-by-step explanation:

1st step

add 3+6

=9

multipy 9*3

=37

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.