What is the equation for 1/3 of the time to paint a room?

If the a and b of your formula mean how many hours it takes each

person, like a = 2 and b = 1, then the formula gives 3/2 or 1 hour and

30 minutes.  This is not reasonable, since one of the painters alone

could do it in 1 hour.

Actually, your formula is UPSIDE DOWN. It should be (a*b)/(a+b).

Here's why.

Let h be the number of hours it takes for the two of them to do it

together. The first person could do it all in a hours, but can paint

only a fraction of the wall working h hours. Assuming a constant rate

of painting, that fraction is h/a. That is, the first painter will

paint h/a of the wall in h hours.  

Similarly, the second painter will paint h/b of the wall in that time.

So, when will they be done? When the whole wall is painted, which

happens whenever those 2 fractions add up to 1.  

You need to solve the following equation:

 (h/a) + (h/b) = 1  

     h*b + h*a = a*b           Multiplying through by a*b

       h*(b+a) = a*b           Factoring out h

             h = (a*b)/(a+b)   Dividing both sides by b+a

Okay, now say 3 painters could do it in a hours, b hours or c hours,

respectively. Let h be the number of hours they all must work to get

it all painted. The first painter finishes h/a of the wall in that

amount of time. The other 2 painters manage to paint h/b of the wall

and h/c of the wall in that time.  Since h is the time to finish the

job, all 3 of these fractions must add up to the whole wall, or 1.  

So you have the equation:

       h     h     h        

      --- + --- + ---  =  1

       a     b     c    

Solve this for h (start by multiplying through by a*b*c) and you will

get the generalized formula for 3 painters. It's not the formula you

wrote above but I think you can finish it off.

I hope this helps.      

Step-by-step explanation:

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560

step-by-step explanation: