For each of the following, state the equation of a perpendicular line that passes through (0, 0). Then using the slope of the new equation, find x if the point P(x, 4) lies on the new line. a. y=3x-1 b. y=1/4 x+2

Below in bold letters.

Step-by-step explanation:

a. y = 3x - 1.

The equation of the perpendicular line will have slope -1/ 3.

So we have the equation y - y1 = -1/3(x - x1)  where (x1, y1) is a point on this perpendicular line.

As the line passes through (0,0):

y - 0 = 1/3(x - 0)

y = -1/3x is the required equation.

If  x,4 is on the line then x  is found by substituting for y:

4 = -1/3 x

x = 4 / -1/3

x = 4*-3 = -12.

b. y = 1/4x + 2

By the same method as in part a:

the equation is y = -4x.

x = 4 / -4 = -1.

image result for what is another name for consecutive interior angles? ​

when two lines are crossed by another line (called the transversal): the pairs of angles on one side of the transversal but inside the two lines are called consecutive interior angles. in this example, these are consecutive interior angles: d and f.

step-by-step explanation: