Find the area. Round to the nearest tenth.
6 in.
5 in.
9 in.
in.

131 1/4 in.²

Step-by-step explanation:

To find the area of the figure, you would have to divide the figure into two parts.  The figure can be divided into two rectangles.

Rectangle 1

The length is 11 3/4 in.  The width is 6 in.

A = lw

A = (11 3/4 in.)(6 in.)

A = 70 1/2 in.²

Rectangle 2

The length is 9 in.  The width is 6 3/4 in.

A = lw

A = (9 in.)(6 3/4 in.)

A = 60 3/4 in.²

Add the two areas together.

70 1/2 in.²  +  60 3/4 in.²  =  131 1/4 in.²

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

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