If you’re pro at geometry, could you please help me with this? :)

From the given information, the value of n is 1. By using that information, the measure of JL is 29.

Step-by-step explanation:

For this problem, we have to not only find the value of n but, we also have to find the value of JL. We are given information in this problem.

ΔABC ≅ ΔJKL

AC = 10n + 19

JL = 9n + 20

From this information, we can conclude that AC and JL are congruent meaning they are equal in measure. So, let's set up an equation where they set equal to each other.

10n + 19 = 9n + 20

Subtract 9n from 10n.

n + 19 = 20

Subtract 19 from 20.

n = 1

So, the value of n is 1. We can use this to find the value of JL.

JL = 9(1) + 20

JL = 9 + 20

JL = 29

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

step-by-step explanation: