Which transformations could be performed to show that AABC is similar to AA"B"C"?
-10
8+
B
6
4
id d
С
2
ic
-10 -8 6 4 -22N14 6
A
8 10 x
B"
a reflection over the x-axis, then a dilation by a scale
factor of 3
a reflection over the x-axis, then a dilation by a scale
factor of
a 180° rotation about the origin, then a dilation by a
scale factor of 3
a 180° rotation about the origin, then a dilation by a
scale factor of
6
-8
10

Hey There!!

The answer to this is: Option D. If two triangles ΔABC and ΔA'B'C' are similar then we take point C of ΔABC to find the transformation performed form C to C'.

Coordinates of C are (0, 3) and the coordinates of C' are (0, -1).

This shows that C is rotated 180° about origin to get the new coordinates as (0, -3) and then new coordinates were dilated by 1/3 which forms C' as (0, -1)

Therefore option D is the correct option.

Hope It Helped!~ ☆

ItsNobody~ ♡

a

step-by-step explanation: