An air traffic controller is tracking two planes. To start, Plane A was at an altitude of 700 meters, and Plane B was at an altitude of 424 meters. Plane A is gaining altitude at 16 meters per second, and Plane B is gaining altitude at 22 meters per second. For each plane, write an expression for the altitude of the plane after x seconds. Write an equation to show when the two planes would be at the same altitude.

since the airplane is moving with constant speed then the distance travelled can be calculated by x=u*t

in km/h would be:

x=640*3.5=2.240 km

in m/s would be:

u=640 km/h= 640.000 m/h =640.000/ 3600 m/s =177.8 m/s

t= 3.5 h= 3.5 * 3600 s=12.600 s

then x=u*t= 177.8*12.600= 2.240.280 m

i really dont know

step-by-step explanation:

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

the answer would be 1 1/72

step-by-step explanation:

you can rewrite the equation by separating the parts and then solving individually:

10-9=1

1/8 - 1/9=

find l c d and then combine:

1 1/72