You are playing basketball with your friends. The height (in feet) of the ball above the ground t seconds after a shot is released from your hand is modeled by the function f(t)= -16t^2 + 32t + 5.2. What is the value of t when the ball is released from your hand ?

2.15 seconds

Step-by-step explanation:

Given the equation of the height (in feet) of the ball above the ground t seconds after a shot is released from your hand modeled by the function

f(t)= -16t² + 32t + 5.2 where t is in seconds.

Note that the value of the height at the point the ball is released from the hand is 0 feet.

To get value of t when the ball is released from your hand, we will substitute f(t) = 0 into the modeled equation as shown;

f(t)= -16t² + 32t + 5.2

-16t² + 32t + 5.2 = 0

Multiply through by 10

-160t² + 320t + 52 = 0

Dividing through by -4

40t² - 80t - 13 = 0

t = 80±√80²-4(40)(-13)/2(40)

t = 80±√6400+2080/80

t = 80±√8480/80

t = 80±92.09/80

t = 80+92.09/80

t = 172.09/80

t = 2.15 secs

Hence, the value of t when the ball is released from your hand is approximately 2.15seconds.

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10

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step-by-step explanation: