Calculate the mean deviation by median (by using the mid-point(x) of leaf weights. b) A fair die is rolled. Find the probability of getting an odd number or a prime number or both?

hello attached below is the required table that is missing and the completed table as well

A) mean deviation = 0.1645

B) 2/3

Step-by-step explanation:

From the table we calculated the midpoint value (x) and c.f

N = 27

median class = 2.35 to 2.45

median = l + [ (N/2) - cf / F ] * H

             = 2.35  + [ (13.5 - 13) / 6 ] *0.1 = 2.3583

hence mean deviation by median

= summation of  fi |xi -M| / summation of fi

= 4.4417 / 27 = 0.1645

B ) probability of getting an odd number or prime number or both

the probability of an odd number = 1/2

also the probability of an even number = 1/2

while the probability of getting neither of them = 1/3

hence the probability of getting odd or prime or both

= 1/2 + 1/2 - 1/3 = 2/3

0.84 dang lotta people are looking for this lol or if you round up its 1 but the overall answer to that is 0.84

step-by-step explanation: