How far have I travelled if I biked at 10mph for hhrs, I walked at 3mph for twice as long as I biked, and ran at 10mph for one quarter as long as I walked? Translate into expression, I will award brainiest!

21h

Step-by-step explanation:

we know that

Speed = distance / time, and as such

distance = speed * time

From the question, we are given that ...

He biked for h hrs -> b

He walked for 2 * b = 2h -> w

He ran for (1/4)(w) = 1/4 * 2h = 1/2 h -> r

The total distance traveled will then be

total distance = distance biked + distance walked + distance ran

recall that we stated that

d = s * t, now we'd apply that here

distance biked = 10 * h = 10h

distance walked = 3 * 2h = 6h

distance ran = 10 * 1/2h = 5h

total distance = 10h + 6h + 5h

Total distance = 21h

8 2/3 is the answer

step-by-step explanation: just use a calculator

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.