The perimeter of a rectangle is 80 inches. The length is 4 inches longer than twice the width. What are the dimensions of the rectangle?

Step-by-step explanation:

Perimeter of a rectangle = 2l + 2w

where

l is the length

w is the width

From the question

Perimeter = 80cm

The length is 4 inches longer than twice the width is written as

l = 4 + 2w

Substitute this into the formula and solve for the width

That's

80 = 2( 4 + 2w) + 2w

80 = 8 + 4w + 2w

6w = 80 - 8

6w = 72

Divide both sides by 6

w = 12 cm

Substitute w = 12 cm into l = 4 + 2w

That's

l = 4 + 2(12)

l = 4 + 24

l = 28cm

Therefore

length = 28 cm

width = 12 cm

Hope this helps you

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1