Hector is flying a kite. He has let out 86 feet of string and is holding it 4 feet off the
ground. If the string is at an angle of
elevation of 42°15’30”, how high is the kite?

Hector's kite is 61.84 feet from the ground.

Step-by-step explanation:

The angle of elevation of the kite is 42°15’30” when converted to decimals, it is ≅

Let the height of the kite to the horizontal of angle of elevation be represented as x. Applying the trigonometric function to the sketch of Hector's kite,

Sin θ =

Sin =

⇒ x = 86 x Sin

      = 86 x 0.6725

     = 57.835

x ≅ 57.84 feet

The height of Hector's kite from the ground = x + 4

                                    = 57.84 + 4

                                   = 61.84 feet

it is probably the graph on the bottom right.

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