Question 1 (1 point) This diagram is a straightedge and compass construction. A is the center
of one circle,
and B is the center of the other. Explain how we know triangle ABC is
equilateral.

Answer/Step-by-step explanation:

Segments AB and AC are both radii of the circle with center A. All radii of a circle are always equal, tgerefire,:

Segments AB and BC are both radii of the circle with center B. All radii of a circle are always equal, therefore:

Thus,

∆ABC has sides AB, AC, and BC, which are all equal (equal radii).

Therefore, ∆ABC is an equilateral triangle.

An equilateral triangle has 3 equal sides.

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

answer: 2x + 2 − 2 = 10 − 2; subtraction property of equality

step-by-step explanation: