HELP Two airplanes leave the airport. Plane A departs at a 44' angle from the runway, and plane B departs at a 40' from the runway Which plane was farther away from

the airport when it was 6 miles from the ground? Round the solutions to the nearest hundredth

Plane A because it was 8.64 miles away

Plane A because it was 8.34 miles away

Plane B because it was 7.83 miles away

Plane B because it was 9.33 miles away

Question 4 Multiple Choice Worth 1 points)

(05.02 MC)

A triangle was dilated by a scale factor of 4. If tan a' =

and FD measures 12 units, how long is EF?

Question 3 (Not Answered). Om

Ned Question

Previous Question

A. Plane B because it was 9.33 miles away

B. 48 units

Step-by-step explanation:

A. Since the airplanes fly at an angle to the runway, their direction forms a triangle with the runway with their height above the ground as the opposite of the angle and their distance from the airport as the hypotenuse.

So for airplane A with 44° angle of departure,

sin44° = y/h where y = height above the ground and h = distance from airport

So h = y/sin44° = 6/sin44° = 8.64 miles

So for airplane B with 40° angle of departure,

sin40° = y/H where y = height above the ground and H = distance from airport

So H = y/sin40° = 6/sin40° = 9.33 miles

Since airplane B is at 9.33 miles away from the airport whereas airplane A is 8.64 miles from the airport, airplane B is farther away.

B. We know that scale factor = new size/original size

Our scale factor = 4 and original size = 12 units. So,

new size = scale factor original size = 4 × 12 = 48 units.

a) 0.25x times 3. (could be wrong on equation.)

b) 2.25 pound of dark chocolate. (can i eat all the chocolate? plz? anyway, again, could be wrong, but i hope im right. all the chocolate together should be 5.25 pounds)

have a good day!

you save $70

discount would be 35% off

step-by-step explanation: