Given below are the analysis of variance results from a Minitab display. Assume that you want to use a 0.05 significance level in testing the null hypothesis that the different samples come from populations with the same mean. Identify the P-value.

hello your question has some missing parts below is the missing part

Given below are the analysis of variance results from a Minitab display. Assume that you want to use a 0.05 significance level in testing the null hypothesis that the different samples come from populations with the same mean.

Identify the p-value.

Source DF SS MS F p

Factor 3 13.500 4.500 5.17 0.011

Error 16 13.925 0.870

Total 19 27.425

A) 0.011 B) 4.500 C) 5.17 D) 0.870

answer :  p-value = 0.011 ( A )

Step-by-step explanation:

using this information

Source DF SS MS F P

Factor 3 13.500 4.500 5.17 0.011

Error 16 13.925 0.870

Total 19 27.425

significance level = 0.05

given that the significance level = 0.05

and

F statistics are given as :  F = 5.17 , F critical = 3.25

hence the p-value = 0.011

from the analysis the p-value is less than the significance level is lower than the significance level

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.