Find the area of the region between the curve y= 2ln(x) and the horizontal axis for 1<= x <= 4

5.09 units

Step-by-step explanation:

Given equation

in the interval

So we integrate in the given interaval

Let us integrate first.

let

Using integration by parts we get

So here

The area of the the region between the curve and horizontal axis is 5.09 units.

80° is the measure of gh

step-by-step explanation:

circle f is congruent to circle j

we have two circle with center f and j.

both circles are congruent. the radius of the circle would be equal.

see the attachment for the circle.

we are given ∠efd ≅ ∠gjh

therefore, arc (ed) = arc (gh)     (∴ circle f is congruent to circle j)

but ∠dfe=80°=arc (ed)

therefore, arc (gh) = 80°

thus, 80° is the measure of gh