The numbers 1-4 are each written on an index card. The 4 cards are put into a bag and 2 of them are drawn at random. What is the probability that the sum of the two cards drawn are greater than 5? I actually know the answer to this question (1/3), however, I don’t know how to solve it; please include an explanation.

Step-by-step explanation:

Write a list of all possible outcomes

1-2

1-3

1-4

2-1

2-3

2-4

3-1

3-2

3-4

4-1

4-2

4-3

There are 12 possible outcomes. How many of them have totals of 6 or 7

I count 4

So the probability is 4/12 = 1/3, just as you said.

Is there an easier way?

You might be able to get the 12 easier.

You have 4 choices for the first number and 3 for the second.

P(12) = 4*3 = 12

Getting 6 or 7 might be somewhat trickier.

4 and 3 make seven. That gives two ways 4-3 and 3-4

4 and 2 make six. That gives 2 more ways 4-2 and 2-4

That's all that's possible.

4 ways make success. The total number of ways is 12.

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it