It would be nice if average values (AV) of integrable functions obeyed the following rules on an interval [a, b]. Do these rules ever hold? Give reasons for your answers. a) AV(f + g) = AV(f) + AV(g)
b) AV(kf) = k*AV(f) for any number k
c) AV(f) ≤ AV(g) if f(x) ≤ g(x) on [a, b]

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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step-by-step explanation:

circumference divided by 3.141592654 then timesthe radius twice

the k side

step-by-step explanation:

plese mark mde brainliest!

answer

you start with $5 and save $10 a week until you have at least $45wer

step-by-step explanation: