Step-by-step explanation:
β 4x = 32 - x^2
Add x^2 to both sides
β 4x +x^2 = 32 -x^2+x^2
β x^2 +4x = 32
Substract 32 from both sides
β x^2+4x -32 =32-32
β x^2 +4x-32=0
That is a quadratic equation
We will use the determinant method
The determinant is b^2-4ac
β a = 1
β b = 4
β c = 32
β b^2-4ac = 4^2 -4Γ1Γ(-32) = 144
144 is positive so the parabola will cross the x-axis two times
β x = (-b -/+ β(b^2-4ac))/2a
β x = (-4 +/- 12) /2
β x = 8/2 or x= -16/2
β x = 4 or x =-8
The solutions are 4 and -8
![How many times does the graph of 4x = 32 - x2 cross the x-axis ?
ΠΠ
0 1
0 2
What are the solution](/tpl/images/0723/4242/3d2cc.jpg)
![How many times does the graph of 4x = 32 - x2 cross the x-axis ?
ΠΠ
0 1
0 2
What are the solution](/tpl/images/0723/4242/49803.jpg)