On a coordinate plane, a piecewise function has 3 lines. The first line has an open circle at (negative 9, negative 2), continues horizontally at y = negative 2, then has an open circle at (0, negative 2). The second line has an open circle at (0, 1), continues up with a positive slope, then has an open circle at (4, 9). The third line has an open circle at (4, negative 2), continues down with a negative slope, then has an open circle at (8, negative 4). What is the domain indicated on the graph for each

 D: x = (-9, 0) U (0, 4) U (4, 8)

Step-by-step explanation:

Line 1:      y = -2               where      -9 < x < 0

Line 2:     y = 2)x + 1        where       0 < x < 4

Line 3:    y = -(1/2)x + 6    where       4 < x < 8

Domain represents the x-values.  Since all of them are open dots, the intervals are strictly less than (<).

-9 < x < 0   and   0 < x < 4   and   4 < x < 8 is the union of these intervals

-9 < x < 0   U   0 < x < 4   U   4 < x < 8

Interval Notation: D: x = (-9, 0) U (0, 4) U (4, 8)

answer: 5

step-by-step explanation: