Pls hel 25 pt and brainiest for whoever answers it right. Find the longest side of a parallelogram with a perimeter of 66ft., If the sides measure 3x + 1 and 2x - 3.

Find the longest side of a parallelogram.

Perimeter of parallelogram = 2 ( a + b )

We know that,

Perimeter of parallelogram = 2 ( a + b )

★ Substituting the values in the above formula,we get:

⇒ 66 = 2 ( 3x + 1 + 2x - 3 )

⇒ 66 = 2 ( 5x - 2 )

⇒ 66/2 = 5x - 2

⇒ 33 = 5x - 2

⇒ 5x - 2 = 33

⇒ 5x = 33 + 2

⇒ 5x = 35

⇒ x = 35/5

⇒ x = 7 ft

Now,

One side,a = 3x + 1

★ Putting the value of x

⇒ 3 × 7 + 1

⇒ 21 + 1

⇒ 22 ft

Other side,b = 2x - 3

★ Putting the value of x

⇒ 2 × 7 - 3

⇒ 14 - 3

⇒ 11 ft

Hence,the longest Side of given parallelogram is 22 ft ( 3x + 1 ) .

(- 1, 0 )

step-by-step explanation:

an x- intercept is where the function crosses the x- axis.

to find the x- intercept/s look for the value of x when f(x) = 0

from the given table there are 3 values of x where f(x) = 0

when x = - 1, x = 2, x = 3

the one that is listed is (- 1, 0 )