Can someone please help me with this?

Hi there! :)

In the question, it is given that AB = 3x - 1 and AC = 8x - 20.

Since AB  = 3x - 1 and B is the midpoint, this means that BC is also 3x - 1. We can express this as an algebraic equation:

8x - 20 = 2(3x - 1)

Distribute the 2 with terms inside of the parenthesis:

8x - 20 = 6x - 2

Subtract 6x from both sides:

2x - 20 = -2

Add 20 to both sides:

2x = 18

Divide both sides by 2:

x = 9

Solve for BC by plugging in the value of x into the formula for AB

(since AB ≅ BC):

3(9) - 1 = 27 - 1 = 26 units.

BC = 26 units.

BC = 5x - 19

Step-by-step explanation:

AC = 8x - 20

AB = 3x - 1

AC = AB + BC

Plug in the corresponding terms to the corresponding variables;

AC = AB + BC

(8x - 20) = (3x - 1) + BC

Isolate the term, BC, subtract 3x - 1 from both sides:

(8x - 20) - (3x - 1) = (3x - 1) - (3x - 1) + BC

BC = 8x - 20 - 3x + 1

BC = 8x - 3x - 20 + 1

BC = 5x - 19

~

1 + (6 / x - 1)

step-by-step explanation:

divide using polynomial division.