HELP ME I GIVE UP PLEASE HELP ASAP

Work Shown:

T = C(3 + AB)

T = 3C + ABC distribute

3C + ABC = T

ABC = T - 3C ... subtract 3C from both sides

(AC)*B = T - 3C

B = (T - 3C)/(AC) divide both sides by AC

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.

(x) - (y) = (1 + 4i)