Of the 727 cases of SI, 203 received two doses of vaccine. Of 1,239 controls, 771 received two doses of vaccine for SI. What is the likelihood of contracting SI with only one dose of vaccine

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Case-Control Calculation Enter only numeric values into the answer line. Place a leading 0 before the decimal and remember to round to two decimal places. Note your answers for the next short essay question. Swine Influenza (SI) is a growing concern at the local Broncoville Health Department in Lawrence, Kansas. You are working for a pharmaceutical company which is developing a human vaccine against SI. You are in charge of testing the vaccine’s effectiveness. You need to determine if one or two doses of vaccine is required to provide immunity. You field test and collect the following information about the vaccine status of persons who did and did not contract SI after getting either one or two doses of vaccine. Develop a 2 x 2 table with the following information: Of the 727 cases of SI, 203 received two doses of vaccine. Of 1,239 controls, 771 received two doses of vaccine for SI. What is the likelihood of contracting SI with only one dose of vaccine?

1. Calculate the incidence of persons with one dose of vaccine for SI

2. Calculate the incidence of persons with two doses of vaccine for SI

3. Calculate the odds ratio of developing SI among those with one dose of vaccine for SI

answer : 1) ≈ 0.53 , (2)  ≈ 0.21,  (3)  ≈ 1.12

Step-by-step explanation:

cases of SI = 727

number of SI cases that received two doses of vaccine = 203

number of SI cases that received one dose of vaccine = 727 -203 = 524

controls = 1239

number of controls that received two doses of vaccine = 771

number of controls that received one dose of vaccine = 1239 - 771 = 468

I) The incidence of persons with one dose of vaccine for SI

= 524 / 992 = 0.528 ≈ 0.53

2) The incidence of persons with two doses of vaccine for SI = 203/974 = 0.208 ≈ 0.21

3) The Odds of SI in one dose group

=  524/468 = 1.119 ≈ 1.12

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.

the probability that a bird is green (.30) is true

step-by-step explanation: