In evaluating a double integral over a region D, a sum of iterated integrals was obtained as follows: ∬Df(x, y)dA=∫5_0∫(2/5)y_0 f(x, y)dxdy+∫7_5∫(7−y)_0 f(x, y)dxdy.
Sketch the region D and express the double integral as an iterated integral with reversed order of integration.
∫b_a∫g2(x)_g1(x) f(x, y)dydx
a= b=
g1(x)= g2(x)=

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.

the aswere is the one with all 8's and the second one is with the 10,8 and 6

step-by-step explanation:

answer is 8x+24

area of vanessa's patio = length × width

given, length = (3x² + 5x + 10)

width = (x² - 3x - 1)

area of vanessa's patio = (3x² + 5x + 10)(x² - 3x - 1)

= 3x²(x² - 3x - 1) + 5x(x² - 3x - 1) + 10(x² - 3x - 1)

= 3x⁴ - 9x³ - 3x² + 5x³ - 15x² - 5x + 10x² - 30x - 10

= 3x⁴ - 4x³ - 8x² - 35x - 10

hence, expression of vanessa's patio = (3x⁴ - 4x³ - 8x² - 35x - 10)

f(x)=4

step-by-step explanation: