Evaluate the surface integral. S x2z2 dS S is the part of the cone z2 = x2 + y2 that lies between the planes z = 3 and z = 5

the answer is b i just did that

step-by-step explanation:

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

6e14 is the answer.