If AY parallel to CX, then find ∠ABC

please help

60°

Step-by-step explanation:

Through point B draw a line m || AY || CX and take two points say E and F on left and right side of point B respectively.

Therefore,

m∠FBC + m∠XCB = 180°..(By interior angle property)

m∠FBC + 130° = 180°

m∠FBC = 180° - 130°

m∠FBC = 50°....(1)

Next,

m∠ABF = m∠BAY... (Alternate angles)

m∠ABC + m∠FBC = 110°

(since, m∠ABF = m∠ABC + m∠FBC)

m∠ABC + 50° = 110° (From equation 1)

m∠ABC = 110° - 50°

the answers c

the answer is b.

step-by-step explanation:

identity property is where 0+whatever number=whatever number. basically 0+ a number.