The three incoming currents at a node in an electrical circuit
measure 0.38 amps, 0.75 amps,
and 0.29 amps. Two of the three
outgoing currents measure 0.48
amps and 0.6 amps. Find the
measure of the third outgoing
Current

PLS HELP

Measure of the third outgoing current will be 0.34 ampere.

Step-by-step explanation:

Kirchhoff's Current Law states that total current entering a circuit's junction is exactly equal to the total current leaving the same junction.

By this rule,

Sum of input three currents = Sum of three outgoing currents

0.38 + 0.75 + 0.29 = 0.48 + 0.6 + i

1.42 = 1.08 + i

i = 0.34

Therefore, measure of the third outgoing current will be 0.34 ampere.

d

step-by-step explanation:

by observation, we can see that the the graph is simply the graph of y = |x| that has been shifted 4 units downwards and 3 units to the left.

we can recognize in choice d :

y = | x + 3 |   - 4 (rewriting in general form)

y = | x - (- 3) |   - 4

the "-4 " term means   that the graph has been shifted by 4 units in the negative y direction

the "-3 " term means   that the graph has been shifted by 3 units in the negative x direction

this matches our observation of the graph described above.

536

step-by-step explanation: