if the bacteria population is doubling every hour, can you estimate the bacteria population at the time of 10 hours?

Bacterial population at the time of 10 hours = 1040000

Step-by-step explanation:

Let the function that defines the bacterial population after 'x' hours is,

p(x) = a(b)ˣ

Where a = Initial population

And 'x' = Duration or time

Since bacterial population is getting doubled every hour,

2a = a(b)¹

b = 2

Therefore, function will be,

p(x) = a(2)ˣ

From the graph attached,

Point (5, 32500) lies on the graph of the function.

32500 = a(2)⁵

a =

Therefore, the function will be,

p(x) = 1015.625(2)ˣ

For x = 10 hours,

p(10) = 1015.625(2)¹⁰

        = 1040000 bacteria

hows it hangin lol

step-by-step explanation:

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb