You take the four Aces, four $2$'s, and four $3$'s from a standard deck of 52 cards, forming a set of $12$ cards. You then deal all $12$ cards at random to four players, so that each player gets three cards. What is the probability that each player gets an Ace, a $2$, and a $3$?

Probability each player gets an ace, a $2 and a $3 = 0.0374

Step-by-step explanation:

The total number of ways to divide the card in triples among four players = 369600 ways

The total number of ways to share the cards such that no card is repeated in each triple = 13824 ways

Probability each player gets an ace, a $2 and a $3 = 13824/369600

Probability each player gets an ace a $2 and a $3 = 0.0374

Note: Further explanation is provided in the attachment.

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47