Mathematics, 13.08.2020 18:01 2025hollowaykyva
1) Determine the discriminant of the 2nd degree equation below:
3x 2 β 2x β 1 = 0
a = 3, b = β2, c = β1
Discriminant β β= b 2 β 4 a c
2) Solve the following 2nd degree equations using BhΓ‘skara's formula:
Ξ = bΒ² - 4.a. c
x = - b Β± βΞ
2a
a) x 2 + 5x + 6 = 0
b)x 2 + 2x + 1 = 0
c) x2 - x - 20 = 0
d) x2 - 3x -4 = 0
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Does the function satisfy the hypotheses of the mean value theorem on the given interval? f(x) = 4x^2 + 3x + 4, [β1, 1] no, f is continuous on [β1, 1] but not differentiable on (β1, 1). no, f is not continuous on [β1, 1]. yes, f is continuous on [β1, 1] and differentiable on (β1, 1) since polynomials are continuous and differentiable on . there is not enough information to verify if this function satisfies the mean value theorem. yes, it does not matter if f is continuous or differentiable; every function satisfies the mean value theorem.
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1) Determine the discriminant of the 2nd degree equation below:
3x 2 β 2x β 1 = 0
a = 3, b = β...
a = 3, b = β...
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