If AB ll CD , EF ll BC, angle bac = 65 and angle dhf = 35 find angle agh

100

Step-by-step explanation:

You know that AB is || to CD, angle BAC ≅ ACD  (this is the theorem where a line connecting the diagnose of two parallel line, the alternative interior angles are equal/ congruent)

You know that EF is || to BC, angle DHF ≅ GHC (these two are  vertically opposite angle which are equal/ this is a theorem)

we now know the angles in ΔGHC where angle GHC=35, angle GCH=65, and angle CGH=80 (subtract other angles from 180)

angle AGH is supplementary w=angle with CGH, which means we subtract 80 from 180, we get 100 will be the angle of AGH

the answer is: the length is 5/6 yards.

give me a or a 5 star rating if this is correct!

step-by-step explanation:

proofs involving isosceles triangles often require special consideration because an isosceles triangle has several distinct properties that do not apply to normal triangles.(more about triangle types) therefore, when you are trying to prove that two triangles are congruent, and one or both triangles, are isosceles you have a few theorems that you can use to make your life easier.

step-by-step explanation:

an isosceles triangle has two congruent sides and two congruent angles. the congruent angles are called the base angles and the other angle is known as the vertex angle. ∠bac and ∠bca are the base angles of the triangle picture on the left. the vertex angle is ∠abc