Find an equation of the tangent plane to the given surface at the specified point. z = ln(x − 8y), (9, 1, 0)

x - 8y - z = 1

Step-by-step explanation:

Data provided according to the question is as follows

f(x,y) = z = ln(x - 8y)

Now the equation for the tangent plane to the surface

For z = f (x,y) at the point P is

Now the partial derivatives of f are

= 1

Now

= -8

So, the tangent equation is

Now after solving this, the following equation arise

z = x - 9 - 8y + 8

z = x - 8y - 1

Therefore

x - 8y - z = 1

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