A pyramid has a square base with an area of 169 ft.² what is the perimeter of the base of the pyramid

The perimeter of the base of the pyramid is 52 square feet.

Given that,

The pyramid contains a square base having an area of 169 square feet.

We know that,

Area of the square = side^2

169 = side^2

So, the side is 13 feet.

So, the perimeter should be

= 4 × sides

= 4 × 13

= 52 feet

Therefore, we can conclude that The perimeter of the base of the pyramid is 52 square feet.

Learn more about the square here: link

52

Step-by-step explanation:

Square root of 169 is 13.

SInce it is a square all sides are same length. So you could do 13x4 or 13+13+13+13. Both will equal to 52.

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)

1/800 is the right answer