The following data set represents the number of new computer accounts registered during ten consecutivedays:43,37,50,51,58,52,4 5,45,58,130(a) Compute the mean, median, IQR, and standard deviation(b) Check for outliers using the 1.5(IQR) rule, and indicate which data points are outliers.(c) Remove the detected outliers and compute the new mean, median, IQR, and standard deviation.(d) Make a conclusion about the effect of outliers on the basic descriptive sta

Outliers have great effect on the mean and standard deviation of the data set

Step-by-step explanation:

Mean =(43+37+50+51+58+52+45+45+58+130)/10

Mean= 579/10

Mean = 57.9

Arranging in ascending order

= 37,43,45,45,50,51,52,58,58,130

Median= (50+51)/2

Median= 101/2

Median= 50.5

IQR= (130-37)/2

IQR= 93/2

IQR= 46.5

Standard deviation

=√(((37-57.9)²+(43-57.9)²+(45-57.9)²+(45-57.9)²+(50-57.9)²+(51-57.9)²+(52-57.9)²+(58-57.9)²+(58-57.9)²+(130-57.9)²)/10)

Standard deviation= 25.1

1.5*(46.5)= 69.75

The number more than 69.75 is 130 and it's the outlier

Without outlier

Mean= (43+37+50+51+58+52+45+45+58)/9

Mean = 449/9

Mean = 49.88

Arranging in ascending order

= 37,43,45,45,50,51,52,58,58

Median= 50

IQR= (58-37)/2

IQR=21/2

IQR=10.5

Standard deviation

the answer to your question is minor arc.