Flying against the wind, a jet travels 1650 miles in 3 hours. Flying with the wind, the same jet travels 3480 miles in 4 hours. What is the rate of the jet in still air and what is the rate of the wind?

Step-by-step explanation:

Let the rate of the plane be x

The rate of the wind be y

Against the wind

Resultant velocity = x-y

1650/3 = x - y

550 = x - y

With the wind

Resultant velocity = x + y

3480/4 = x + y

870 = x + y

Solve equation simultaneously

Add both equations

870+550 = x+y+x-y

1420 = 2x

x = 710

x + y = 870

y=870 - 710

y = 160

The rate of jet in still air = 710 mph

The rate of wind = 160 mph

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can i see the following ?

step-by-step explanation:

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180