What is the standard form of function f ?

f(x) = 4x² + 48x + 149

Step-by-step explanation:

f(x) = 4(x + 6)² + 5

The above expression can be written as: f(x) = ax² + bx + c, by doing the following:

1. Expand (x + 6)²

(x + 6)² = (x + 6)(x + 6)

(x + 6)(x + 6)

x(x + 6) + 6(x +6)

x² + 6x + 6x + 36

x² + 12x + 36

(x + 6)² = x² + 12x + 36

2. Substitute x² + 12x + 36 for (x + 6)² in

f(x) = 4(x + 6)² + 5

This is illustrated below:

f(x) = 4(x + 6)² + 5

(x + 6)² = x² + 12x + 36

f(x) = 4(x² + 12x + 36) + 5

Clear bracket

f(x) = 4x² + 48x + 144 + 5

f(x) = 4x² + 48x + 149

Therefore, the standard of the function:

f(x) = 4(x + 6)² + 5

is

f(x) = 4x² + 48x + 149

-50/3

step-by-step explanation: