What is the area of triangle BCD to the nearest tenth of a square centimeter? Use special right triangles to help find the height. Show your work.

21.7 cm²

Step-by-step explanation:

Given:

Right ∆BCD,

<D = 60°

adjacent length = 5 cm

Required:

Area of ∆BCD

SOLUTION:

Step 1: find the height (opposite side length) of ∆BCD

Multiply both sides by 5

(approximated)

Step 2: find the area of ∆BCD

Area = ½*base*height

Area = ½*5*8.7 = 21.7 cm² (nearest tenth)

none cuz there are no "following statements" regarding the question

step-by-step explanation:

b

step-by-step explanation:

it have 5 sides and 5 identicle angle.the rest does not have the same property as b.

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