4. The general population (Population 2) has a mean of 30 and a standard deviation of 5, and the cutoff Z score for significance in a study involving one participant is 1.96. If the raw score obtained by the participant is 45, what decisions should be made about the null and research hypotheses?

The null hypothesis is rejected and  research hypotheses is supported

Step-by-step explanation:

From the question we are told that

    The population mean is  

     The standard deviation is

      The sample size is  n =  1

      The  cutoff Z score for significance is  

       The mean score is  

Generally the test hypothesis is mathematically represented as

=>        

=>        

From the obtained value  we can see that

Hence the null hypothesis is rejected and  research hypotheses is supported

the answer is 844

step-by-step explanation:

it is 844 because if you add 836.50 + 7.5 you will get 844

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3