You want to borrow three rock CDs from your friend. She loves math puzzles and she always makes you solve one before you can borrow her stuff. Here’s the puzzle: Before you borrow three CDs, she will have 39 CDs. She will have half as many country CDs as rock CDs, and one-fourth as many soundtracks as country CDs. How many of each type of CD does she have after you borrow three rock CDs?

interesting puzzle,

total CDs=

country CDs $c$ is half of rock CDs $r$, $r=2c$

and one fourth of soundtrack $s$ as country CDs , $c=4s$

express in common variable s, $r+c+s=39$

$2(4s)+4s+s=39 \implies s=3$

so $c=12$ and $r=24$

after borrowing 3 rock CDs, there be $21$ rock CDs rest will be same

i dont know if you cant find a way its best to actually add all of them start from 105 tho

step-by-step explanation:

step-by-step explanation:

no, her answer is not correct.   we square the lengths of all sides and then determine whether the pythagorean theorem holds here:

9² + 15² = 306.   this is not equal to the square of the longest side ( that square being 395.   answer c is correct.