What is the simplified form of the following expression? 2 StartRoot 18 EndRoot + 3 StartRoot 2 EndRoot + StartRoot 162 EndRoot

2*√18 + 3*√2 + √162 = 18*√2

Step-by-step explanation:

I guess that the equation is:

2*√18 + 3*√2 + √162

And we want to simplify it.

first 18 = 9*2

then we can write:

2*√18 = 2*√(9*2) = 2*3*√2 = 6*√2

and 162/9 = 18

then we can write:

√162 = √(9*18) = √9*√18 = 3√18

now we can use the previous step: √18 = 3*√2

and:

√162 = 3*(3*√2) = 9*√2

now we can write our equation as:

6√2 + 3√2 + 9√2 = (6 + 3 + 9)√2 = 18*√2

And now we can not simplify it further more, so here we end.

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

english, cause i can’t you